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 Algebra Pre-Algebra and Basic Algebra Math Forum

 May 3rd, 2014, 04:38 AM #1 Newbie   Joined: May 2014 From: UK Posts: 4 Thanks: 0 Parabolas Hello there, I've got the following problem that I require some help with: x^2-3y-4=0, I need to find all values of (x,y) that are integers. Has anybody got any ideas? Ty in advance, Bearz May 3rd, 2014, 05:54 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,674 Thanks: 2654 Math Focus: Mainly analysis and algebra $$y = \frac{1}{3}(x - 2)(x + 2)$$ Thus, given $x \in \mathbb{Z}$, $x - 2 = 3k$ and $x+2 =3k$ ($k \in \mathbb{Z}$) give $y \in \mathbb{Z}$. So, all $x = 3k \pm 2$ are integer solutions which is the same as saying all integers not divisible by three. We can also investigate the $y$ values. $$y = k(3k \pm 4) = 3k^2 \pm 4k$$ Thanks from Olinguito and Bearz Last edited by v8archie; May 3rd, 2014 at 06:05 AM. Tags parabolas Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post sumi123 Algebra 2 August 5th, 2012 10:26 AM anthonye Algebra 3 May 8th, 2012 05:52 AM jkh1919 Algebra 1 September 25th, 2011 08:15 PM sallyyy Algebra 3 November 14th, 2010 10:46 AM ILoveISO Algebra 11 November 23rd, 2009 08:44 PM

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