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April 25th, 2014, 10:18 AM   #1
The
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help me with this exponential real quick please

alright
query: (5-3ln(7)) - (2-3ln(4))
shouldn't this equal 3-3ln(4/7)?
the answer that i should get is 3-3ln(7/4)
can someone explain why exactly this is..?
thanks

i may be missing something really big here
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April 25th, 2014, 10:25 AM   #2
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Math Focus: सामान्य गणित
3 - 3 ln(7/4)
is correct
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April 25th, 2014, 10:36 AM   #3
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Not exacly the answer i wanted

it is correct yes, but shouldn't 3ln4 - 3ln7 be 3ln(4/7)? Since it is the 4 minus the 7?
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April 25th, 2014, 10:36 AM   #4
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Math Focus: सामान्य गणित
let y = ln 7 , x = ln 4
or, e^y = 7, e^x = 4
then,
7/4 = (e^y)/(e^x) = e^(y-x)
thus, y - x = ln(7/4)
(5 - 3y) - (2 - 3x)
5 - 2 - 3 (y - x)
3 - 3 ln(7/4)
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April 25th, 2014, 10:39 AM   #5
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Thanks a lot mate!
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April 25th, 2014, 10:40 AM   #6
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Math Focus: सामान्य गणित
yes your question has 4 minus 7
but your answer also has minus infront of ln
its like taking minus common and having - ( 7 minus 4)
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April 25th, 2014, 10:40 AM   #7
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(5-3ln(7))-(2-3ln(4))=

5-3ln(7)-2+3ln(4)=

5-2+3ln(4)-3ln(7)=

3 + 3(ln(4)-ln(7))=

3+3ln(4/7); log(n)-ln(m)=ln(n/m)
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April 25th, 2014, 10:43 AM   #8
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thanks for THANKS
your thanks is the first thanks that i've earned in mmf
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