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April 20th, 2014, 06:30 AM   #1
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Bearing and Distance

Town Q is 20km due north of P. The bearing of town R from Q is . If R is 8 km from Q. calculate:
(a) the bearing of R from P, to the nearest degree:

(b) how far north of P, R is, correct to 2 significant figures;
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April 20th, 2014, 03:33 PM   #2
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Have you drawn a diagram? As this is a trigonometry problem, can you put it in the trigonometry subforum?
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April 20th, 2014, 08:35 PM   #3
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Drawing the diagram is my main problem. If you can help me with the drawing, I can attempt the working.
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April 20th, 2014, 09:59 PM   #4
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Quote:
Originally Posted by chikis View Post
town q is 20km due north of p. The bearing of town r from q is . If r is 8 km from q. Calculate:
(a) the bearing of r from p, to the nearest degree:
(b) how far north of p, r is, correct to 2 significant figures;
Code:
n

q


      r





p
I'm always "confused" when bearings are used (point N added);
I make angle NQR = 140 degrees, so angle PQR = 40 degrees.
With PQ = 20 and QR = 8, then easy....

Am I correct "bearingwise"?
If so, I'll be quite pleased with myself
and will treat myself to a Mr.Big chocolate bar...

Anybody know why [code] changes capitals
to lowercase, as is the case with above?

Last edited by Denis; April 20th, 2014 at 10:02 PM.
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April 21st, 2014, 08:38 PM   #5
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That's correct.

If RS is an altitude of triangle PQR, RS = QR*sin(40°), and QS = QR*cos(40°).
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