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 April 20th, 2014, 06:30 AM #1 Senior Member     Joined: Jan 2012 Posts: 725 Thanks: 7 Bearing and Distance Town Q is 20km due north of P. The bearing of town R from Q is $140^0$. If R is 8 km from Q. calculate:(a) the bearing of R from P, to the nearest degree: (b) how far north of P, R is, correct to 2 significant figures;
 April 20th, 2014, 03:33 PM #2 Global Moderator   Joined: Dec 2006 Posts: 20,262 Thanks: 1958 Have you drawn a diagram? As this is a trigonometry problem, can you put it in the trigonometry subforum?
 April 20th, 2014, 08:35 PM #3 Senior Member     Joined: Jan 2012 Posts: 725 Thanks: 7 Drawing the diagram is my main problem. If you can help me with the drawing, I can attempt the working.
April 20th, 2014, 09:59 PM   #4
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Quote:
 Originally Posted by chikis town q is 20km due north of p. The bearing of town r from q is $140^0$. If r is 8 km from q. Calculate:(a) the bearing of r from p, to the nearest degree: (b) how far north of p, r is, correct to 2 significant figures;
Code:
n

q

r

p
I'm always "confused" when bearings are used (point N added);
I make angle NQR = 140 degrees, so angle PQR = 40 degrees.
With PQ = 20 and QR = 8, then easy....

Am I correct "bearingwise"?
If so, I'll be quite pleased with myself
and will treat myself to a Mr.Big chocolate bar...

Anybody know why [code] changes capitals
to lowercase, as is the case with above?

Last edited by Denis; April 20th, 2014 at 10:02 PM.

 April 21st, 2014, 08:38 PM #5 Global Moderator   Joined: Dec 2006 Posts: 20,262 Thanks: 1958 That's correct. If RS is an altitude of triangle PQR, RS = QR*sin(40°), and QS = QR*cos(40°).

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# Town Q is 20km due north of P. The bearing of town R from Q is 140 degrees. If R is 8km from Q, calculate the bearing of R from P.

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