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April 20th, 2014, 05:30 AM  #1 
Senior Member Joined: Jan 2012 Posts: 745 Thanks: 7  Bearing and Distance
Town Q is 20km due north of P. The bearing of town R from Q is . If R is 8 km from Q. calculate: (a) the bearing of R from P, to the nearest degree: (b) how far north of P, R is, correct to 2 significant figures; 
April 20th, 2014, 02:33 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,833 Thanks: 2161 
Have you drawn a diagram? As this is a trigonometry problem, can you put it in the trigonometry subforum?

April 20th, 2014, 07:35 PM  #3 
Senior Member Joined: Jan 2012 Posts: 745 Thanks: 7 
Drawing the diagram is my main problem. If you can help me with the drawing, I can attempt the working.

April 20th, 2014, 08:59 PM  #4  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038  Quote:
Code: n q r p I make angle NQR = 140 degrees, so angle PQR = 40 degrees. With PQ = 20 and QR = 8, then easy.... Am I correct "bearingwise"? If so, I'll be quite pleased with myself and will treat myself to a Mr.Big chocolate bar... Anybody know why [code] changes capitals to lowercase, as is the case with above? Last edited by Denis; April 20th, 2014 at 09:02 PM.  
April 21st, 2014, 07:38 PM  #5 
Global Moderator Joined: Dec 2006 Posts: 20,833 Thanks: 2161 
That's correct. If RS is an altitude of triangle PQR, RS = QR*sin(40°), and QS = QR*cos(40°). 

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