Algebra Pre-Algebra and Basic Algebra Math Forum

 April 17th, 2014, 01:03 PM #1 Senior Member   Joined: Nov 2013 Posts: 434 Thanks: 8 ads solve abs(x^2-abs(x))=2 Last edited by mared; April 17th, 2014 at 01:05 PM.
 April 17th, 2014, 05:29 PM #2 Senior Member   Joined: Dec 2013 From: Russia Posts: 327 Thanks: 108 To remove the outer absolute value, solve $x^2-|x|=\pm 2$. To remove the inner absolute value, consider two cases: (1) $x<0$ and $|x|=-x$ or (2) $x\ge0$ and $|x|=x$.
 April 18th, 2014, 05:38 PM #3 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,674 Thanks: 2654 Math Focus: Mainly analysis and algebra Remember that $|x|^2 =x^2$ The first step is then to square the equation, noting that no solutions are added. Last edited by v8archie; April 18th, 2014 at 06:37 PM.