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adssolve abs(x^2-abs(x))=2 |

To remove the outer absolute value, solve $x^2-|x|=\pm 2$. To remove the inner absolute value, consider two cases: (1) $x<0$ and $|x|=-x$ or (2) $x\ge0$ and $|x|=x$. |

Remember that $|x|^2 =x^2$ The first step is then to square the equation, noting that no solutions are added. |

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