My Math Forum

My Math Forum (http://mymathforum.com/math-forums.php)
-   Algebra (http://mymathforum.com/algebra/)
-   -   ads (http://mymathforum.com/algebra/42988-ads.html)

mared April 17th, 2014 01:03 PM

ads
 
solve abs(x^2-abs(x))=2

Evgeny.Makarov April 17th, 2014 05:29 PM

To remove the outer absolute value, solve $x^2-|x|=\pm 2$. To remove the inner absolute value, consider two cases: (1) $x<0$ and $|x|=-x$ or (2) $x\ge0$ and $|x|=x$.

v8archie April 18th, 2014 05:38 PM

Remember that $|x|^2 =x^2$

The first step is then to square the equation, noting that no solutions are added.


All times are GMT -8. The time now is 08:44 PM.

Copyright © 2019 My Math Forum. All rights reserved.