April 16th, 2014, 02:41 PM |
#1 |

Senior Member Joined: Nov 2013 Posts: 434 Thanks: 8 | solve
x+y+z=56 (x+z)(z+y)=1568 x^2+y^2=z^2 |

April 16th, 2014, 04:32 PM |
#2 | |

Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408 | Hello, mared! Quote:
[3] says we have a Pythagorean triple. [1] says its sum is 56. The answer is: $\displaystyle \:(x,y,z) \:=\:(7,24,25)\:\text{ or }\:(24,7,25)$ | |