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April 13th, 2014, 04:52 AM  #1 
Newbie Joined: Feb 2014 Posts: 17 Thanks: 0  fraction and bracket equation
Hi, I have attempted to work this out (several times). If someone who knows what their doing can look at it I will be happy. The equation is: 3/7(x  2) = 2 Multiply out fraction: 3/7 X 3 (x  2) = 2 X 7 Simplify: 7(x  2) =14 Multiply out brackets: 7 X x  2 = 14 Remove 2: 7x = 14 Remove 7: x = 6 So 3/7(62) = 1.7 Would this round to 2. 
April 13th, 2014, 05:35 AM  #2 
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  This is a joke, right? You managed to make an unheardof error in every step! 
April 13th, 2014, 08:47 AM  #3 
Newbie Joined: Feb 2014 Posts: 17 Thanks: 0 
Yes, its not funny. I am very bad at maths. It actually really upsets me I am not able to use maths well. If you give me a hint of how to start I will get back to you. Thanks. 
April 13th, 2014, 12:35 PM  #4 
Senior Member Joined: Apr 2014 From: Greater London, England, UK Posts: 320 Thanks: 156 Math Focus: Abstract algebra 
For a start you need to write your equations clearly to avoid confusion. For instance, does 3/7(x  2) mean $\displaystyle \frac3{7(x2)}$ or $\displaystyle \frac37(x2)$? From what you wrote at the end of your postI should say it’s $\displaystyle \frac37(x2)$. Let’s start with where you made your first mistake: You want to multiply both sides by 7. The part I’ve highlighted in red is incorrect. Can you rectify it? 
April 16th, 2014, 02:13 AM  #5  
Newbie Joined: Feb 2014 Posts: 17 Thanks: 0  Quote:
Yes it is how you have done it but I don't know how to put in the fraction signs. I have just copied your codes in just now. The equation is: $\displaystyle \frac37(x2)$ = 2 Multiply out fraction: 3 (x 2) = 14 Multiply out brackets: 3x 6 = 14 Add 6: 3x = 14 Divide by 3: x = 6.66... Round to 6.7? Check: $\displaystyle \frac37(6.7 2)$. = 2 What are your thoughts on this? I keep getting decimal numbers but don't know if this is right? Thanks.  
April 16th, 2014, 03:11 AM  #6 
Senior Member Joined: Apr 2014 From: Greater London, England, UK Posts: 320 Thanks: 156 Math Focus: Abstract algebra 
Your working is almost perfect. The only mistake you made is here: The righthand side should be $14+6=20$ so the answer should be $x=\dfrac{20}3$. But everything else you did was correct. Well done! By the way, if you don’t like decimal numbers you can always leave your answer as a fraction. 
April 16th, 2014, 05:01 AM  #7  
Newbie Joined: Apr 2014 From: The Netherlands Posts: 7 Thanks: 2  Quote:
When multiplying out the fraction, you indeed do this. But, when adding 6 to the left hand side, you are not adding 6 to the right hand side. There's nothing wrong with having a fraction as an answer, you don't necessarily have to round your answer. Also, note that only the fraction will be the exact answer. Last edited by jyrdo; April 16th, 2014 at 05:03 AM.  
April 17th, 2014, 11:03 AM  #8 
Newbie Joined: Feb 2014 Posts: 17 Thanks: 0 
Many thanks. I see now I have been missing out a lot of steps in doing the calculation. I can only get better with practice. Kind regards. 

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