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April 11th, 2014, 09:10 AM  #1 
Member Joined: Jan 2014 From: Tashkent, Uzbekistan Posts: 52 Thanks: 2  Hangglider and racing car's race. Time of catching up
Hi! I'm difficulty in the solving of following problem: At 7.40 am the weather was fine and the velocity of air was 38.5 km/h. Hangglider flew from the mountain and started flying in a straight line. At 14.40 the weather has changed, wind speed increased to 70 km/h and keeps to increase by 10 km/h in every 45 minutes. At 15.37 racing car with the velocity 240 km/h (wind is not impact to the velocity of the car) dashed in pursuit of. At what time the car catches the hangglider. Could you please help me to solve this interesting problem? Any help will be appreciated! Thanks! 
April 11th, 2014, 10:42 AM  #2  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,320 Thanks: 936  Quote:
BUT don't we have to know WHERE the car is at 15.37; like, how far behind the glider? OR are we to ASSUME the car starts off from where the glider originally started off?  
April 11th, 2014, 05:24 PM  #3  
Member Joined: Jan 2014 From: Tashkent, Uzbekistan Posts: 52 Thanks: 2  Quote:
In the problem it's not mentioned, so you're right! We assume the car starts off from where the glider originally started off. Thanks!  
April 11th, 2014, 07:52 PM  #4 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,320 Thanks: 936  Code: TIME DISTANCE SPEED (Glider) 7:40 0 14:40 269.5 269.5 38.5 15:25 52.5 322.0 70 15:37* 16.0 338.0* 80 16:10 44.0 382.0 80 16:55 67.5 449.5 90 17:40 75.0 524.5 100 17:55 27.5 552.0 110 (Car) 15:37* 0 17:55 552.0 552.0 240 At 17:55, car caught up to glider. 
April 12th, 2014, 07:13 AM  #5 
Member Joined: Jan 2014 From: Tashkent, Uzbekistan Posts: 52 Thanks: 2  Denis, thank you very much! I got it.


Tags 
car, catching, hangglider, race, racing, time 
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