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April 2nd, 2014, 05:07 PM   #11
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Originally Posted by v8archie View Post
You can create your own by expanding $$\prod_{i=1}^{5}{(x - a_i)}$$ where the $a_i$ are whatever roots you decide to select (and all will be solveable). You could even replace a pair of real roots with a quadratic having no real solutions.

Or, you can create $$\sum_{i=0}^{5}{a_i x^i}$$ to get (probably) insolvable equations.

Both are approaches that have already been suggested. Why do we have to do the (trivial) work of selecting five or six numbers for you?
So, u can help me with some of them
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April 2nd, 2014, 05:14 PM   #12
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Are you now saying you want examples which do have solutions, but without being told what the solutions are?
YES
And a lot of them if U CAN
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April 2nd, 2014, 08:42 PM   #13
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19x^23 - 7x^17 + 3x^11 - 15 = 0

One solution will do....
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April 2nd, 2014, 09:40 PM   #14
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Everything quintic have solutions. Say, how about, $x^5 - x - 1$?
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April 3rd, 2014, 07:53 PM   #15
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Originally Posted by Denis View Post
19x^23 - 7x^17 + 3x^11 - 15 = 0

One solution will do....
Amazing
That's what I'm looking for
Thanks Denis
Please more like this. .
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April 7th, 2014, 07:31 AM   #16
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Up, Up. .
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April 7th, 2014, 08:25 AM   #17
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That's not quintic.
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