My Math Forum Need help

 Algebra Pre-Algebra and Basic Algebra Math Forum

April 2nd, 2014, 05:07 PM   #11
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From: illinois, usa

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Quote:
 Originally Posted by v8archie You can create your own by expanding $$\prod_{i=1}^{5}{(x - a_i)}$$ where the $a_i$ are whatever roots you decide to select (and all will be solveable). You could even replace a pair of real roots with a quadratic having no real solutions. Or, you can create $$\sum_{i=0}^{5}{a_i x^i}$$ to get (probably) insolvable equations. Both are approaches that have already been suggested. Why do we have to do the (trivial) work of selecting five or six numbers for you?
So, u can help me with some of them

April 2nd, 2014, 05:14 PM   #12
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Quote:
 Originally Posted by skipjack Are you now saying you want examples which do have solutions, but without being told what the solutions are?
YES
And a lot of them if U CAN

 April 2nd, 2014, 08:42 PM #13 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 19x^23 - 7x^17 + 3x^11 - 15 = 0 One solution will do....
 April 2nd, 2014, 09:40 PM #14 Math Team     Joined: Mar 2012 From: India, West Bengal Posts: 3,871 Thanks: 86 Math Focus: Number Theory Everything quintic have solutions. Say, how about, $x^5 - x - 1$?
April 3rd, 2014, 07:53 PM   #15
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Joined: Mar 2014
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Quote:
 Originally Posted by Denis 19x^23 - 7x^17 + 3x^11 - 15 = 0 One solution will do....
Amazing
That's what I'm looking for
Thanks Denis

 April 7th, 2014, 07:31 AM #16 Newbie   Joined: Mar 2014 From: illinois, usa Posts: 9 Thanks: 0 Up, Up. .
 April 7th, 2014, 08:25 AM #17 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,671 Thanks: 2651 Math Focus: Mainly analysis and algebra That's not quintic.

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