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 March 30th, 2014, 09:12 AM #1 Senior Member   Joined: Mar 2012 From: Belgium Posts: 654 Thanks: 11 function equation Find all so that March 30th, 2014, 07:39 PM   #2
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Quote:
 Originally Posted by gelatine1 Find all so that

or

?

The latter makes more sense to me on the face of it. March 30th, 2014, 07:54 PM #3 Global Moderator   Joined: Dec 2006 Posts: 21,036 Thanks: 2274 For the equation originally posted, f(x) ≡ 0 and f(x) ≡ -x work. I suspect they are the only solutions, but I don't have a proof of that. March 31st, 2014, 10:39 AM #4 Senior Member   Joined: Mar 2012 From: Belgium Posts: 654 Thanks: 11 Yes, that is correct. Although I have a proof (in Dutch) I don't completely understand it. But at least your solutions are correct  March 31st, 2014, 09:56 PM #5 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,693 Thanks: 2677 Math Focus: Mainly analysis and algebra Well, I can see those two solutions: If we assume that there exists a value of y for which f(y) = 0, then we have that f(xy) = 0 for all x. This gives us two possibilities:f(x) = 0 for all x; or y = 0, which means that f(0) = 0. The first is clearly degenerate, so let's take f(0) = 0. Note that we got this far on the basis that there exists at least one value for which f(y) = 0. Moving on, if we let x = 0 in the functional equation, we get because f(0) = 0. Now, if we assume that there exists an inverse function g(x) such that g(f(x)) = x, we can apply this function to both sides of our equation to get so for all y. Thus, if there exists a value of x for which f(x) = 0, we can say that I can't make anything work if we assume that there is no value for which f(x) = 0. That is, I can neither see such a function nor prove that no such function exists. Tags equation, function signum function equation

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