My Math Forum Please this is urgent!!

 Algebra Pre-Algebra and Basic Algebra Math Forum

 March 29th, 2014, 08:12 AM #1 Newbie   Joined: Mar 2014 From: London Posts: 2 Thanks: 0 Please this is urgent!! IMPORTANT NOTE In the following, x^2, x^3, mean "x squared", "x cubed", respectively. Generally, a^n means "a to the power n". 1. Y is proportional to (1 - X). When X = 2, Y = -2. Find the value of X required to give Y = 6. 2. Z is proportional to (X - 2). When X = 1, Z = 1. Enter the value of X required to give Z = -2. 3. X is inversely proportional to Y. When X = 2, Y = 3. Find the value of Y required to give X = 4 [Express your as a decimal correct to 2sf 4. V is proportional to (T+1)^2. When T= 1, V = 1. Enter (as a decimal) the value of V when T = 2.
 March 29th, 2014, 10:16 AM #2 Math Team     Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233 The words 'a is proportional to b' translate $a= kb$ So your question 1) translates $Y= k(1 - X)$ Make the substitutions from the given info and solve for k $-2= k[1 - (2)]$ $-2= - k$ $k= 2$ So the relation for 1) is $Y= 2(1 - X)$ Now use Y = 6 to solve for X $6= 2(1 - X)$ $6= 2 - 2X$ $4= -2X$ $X= -2$ Your question 2) is done similarly. The words 'a is inversely proportional to b' translate $a= \frac{k}{b}$ So your question 3) translates $X= \frac{k}{Y}$ Proceed as i have done for question 1) , substitute the given info , solve for k , then use the relation to solve for Y. For your question 4) you should get $V= k(T + 1)^2$ Now do as shown above.

 Tags urgent

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post bogazichili Advanced Statistics 0 April 3rd, 2009 01:38 AM tcabaco Algebra 1 March 2nd, 2009 03:52 AM nikolany Number Theory 2 November 5th, 2008 11:51 PM gladtoknow Algebra 1 November 5th, 2008 12:30 PM kingdomofthenight Advanced Statistics 1 September 18th, 2008 03:04 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top