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October 20th, 2008, 08:28 PM  #1 
Newbie Joined: Jun 2008 Posts: 20 Thanks: 0  Simplification help
Could anybody please explain how [attachment=1:2qzns35k]1.gif[/attachment:2qzns35k] simplifies to [attachment=0:2qzns35k]2.GIF[/attachment:2qzns35k]? I'm not much good with throwing rational exponents around Thanks! 
October 20th, 2008, 08:36 PM  #2 
Senior Member Joined: Jul 2008 Posts: 895 Thanks: 0  Re: Simplification help
Your problem might not be so much exponents as fractions? Multiply AND divide 3x^(7/3) by 3x^(2/3) to have a common denominator for dividing [[color=#FF0000]Did I say, "dividing"? I mean adding[/color]] fractions. You should know how to multiply the two, or you had better go back over the fundamental rules for multiplying exponents (a^b)(a^c) = a^(b+c). You should know how to express the top part as a sum over a common denominator, that is as a single fraction. You now have one fraction divided by something. Apply this rule: (a/b)/c = (a/b)/(c/1) = (a/b)(1/c) = a/(bc) The end result might be factored, but to no further advantage here. 
October 20th, 2008, 08:45 PM  #3 
Newbie Joined: Jun 2008 Posts: 20 Thanks: 0  Re: Simplification help
Ah! It makes sense now, thanks. Our Calc teacher doesn't make us simplify anything once the Calculus is done, but I've been doing all the problems anyway just to give myself the practice since I've been away from school (and math) for such a long time. Thanks for the help!

October 21st, 2008, 02:17 PM  #4  
Senior Member Joined: Jul 2008 Posts: 895 Thanks: 0  Re: Simplification help Quote:
 

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