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 March 25th, 2014, 12:59 PM #1 Senior Member   Joined: May 2012 Posts: 205 Thanks: 5 simplify Will someone please simplify this, with detailed steps? Thanks. ((cosx-(cosx)^2-(sinx)^2))/(1-cosx)^2
March 25th, 2014, 04:03 PM   #2
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Joined: Dec 2006
From: Lexington, MA

Posts: 3,267
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Re: simplify

Hello, Kinroh!

Quote:
 $\text{Simplify: }\:\frac{\cos x\,-\,\cos^2x\,-\,\sin^2x}{(1\,-\,\cos x)^2}$

$\text{W\!e have: }\:\frac{\cos x \,-\,\overbrace{(\cos^2x\,+\,\sin^2x)}^{\text{This is 1}}}{(1\,-\,\cos x)^2} \;=\;\frac{\cos x\,-\,1}{(1\,-\,\cos x)^2} \;=\;\frac{-(1\,-\,\cos x)}{(1\,-\,\cos x)^2} \;=\;\frac{-1}{1\,-\,\cos x}$

$\text{Therefore: }\:\frac{1}{\cos x\,-\,1}$

 March 25th, 2014, 05:37 PM #3 Senior Member   Joined: May 2012 Posts: 205 Thanks: 5 Re: simplify Thank you.
 March 25th, 2014, 07:38 PM #4 Senior Member   Joined: May 2012 Posts: 205 Thanks: 5 Re: simplify how about the derivative of tanx/(1+tanx)
 March 26th, 2014, 06:09 AM #5 Global Moderator   Joined: Dec 2006 Posts: 21,015 Thanks: 2250 That's a calculus question. Can you post it in the calculus subforum?

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