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April 17th, 2014, 03:43 PM   #11
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Quote:
Originally Posted by the john View Post
Also, if the circle doesn't require having such tangent lines then . . .
With the smaller radius, (x - 1)² + (y - 4)² = 1 or x² + y² - 2x - 8y + 16 = 0. Note that the center (1, 4) is the midpoint between the other two circles' centers.
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