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March 3rd, 2014, 03:23 AM   #1
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Help me to find this



What is value of 6y=?
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March 3rd, 2014, 11:31 AM   #2
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Re: Help me to find this

In the 2nd term: is that x^(2y) or x^2 times y ?

If it's x^(2y), then it's an almost "impossible" equation, solvable only (I think) by numeric methods.
It can be simplified to:
x^3 + x^2 - 4xy^2 + 2x*(2y) + 4xy - 4y^2 = 0
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March 4th, 2014, 02:39 AM   #3
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Re: Help me to find this

oohh,how about if we use 2x^2y?
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March 4th, 2014, 03:12 AM   #4
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Re: Help me to find this

Quote:
Originally Posted by naufalzhafran
oohh,how about if we use 2x^2y?
Well, if that means 2x^2 times y, it's a little better, but still a big mess.
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March 4th, 2014, 03:39 AM   #5
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Re: Help me to find this

Sorry,i got this question from my friend and he couldn't find the answer. If the question change into:



What is the value of 6y?
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March 4th, 2014, 03:52 AM   #6
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Re: Help me to find this

Ok, then you have a quadratic in "y":

(4x + 4)y^2 - (2x^2 + 4x)y - x^2 - x^3 = 0

Solve for y, then multiply by 6 since for some silly reason you're asking for value of 6y
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March 4th, 2014, 11:26 AM   #7
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Perhaps the friend got it written incorrectly.

If the equation should have been

that simplifies to 4y - x = 2y + x, so that 6y = 3x + 3x.
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March 4th, 2014, 04:31 PM   #8
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Re: Help me to find this

Quote:
Originally Posted by naufalzhafran
Any reason for that "friend" of yours to write the equation that way?
Example:
x/d - y/d = d is simply x - y = d^2
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