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 March 3rd, 2014, 03:23 AM #1 Newbie   Joined: Feb 2014 Posts: 6 Thanks: 0 Help me to find this $\frac{8y^2+4xy^2}{2y+x} - \frac{x^3+2x^2^y}{x+2y}= 2y+x$ What is value of 6y=?
 March 3rd, 2014, 11:31 AM #2 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Re: Help me to find this In the 2nd term: is that x^(2y) or x^2 times y ? If it's x^(2y), then it's an almost "impossible" equation, solvable only (I think) by numeric methods. It can be simplified to: x^3 + x^2 - 4xy^2 + 2x*(2y) + 4xy - 4y^2 = 0
 March 4th, 2014, 02:39 AM #3 Newbie   Joined: Feb 2014 Posts: 6 Thanks: 0 Re: Help me to find this oohh,how about if we use 2x^2y?
March 4th, 2014, 03:12 AM   #4
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Re: Help me to find this

Quote:
 Originally Posted by naufalzhafran oohh,how about if we use 2x^2y?
Well, if that means 2x^2 times y, it's a little better, but still a big mess.

 March 4th, 2014, 03:39 AM #5 Newbie   Joined: Feb 2014 Posts: 6 Thanks: 0 Re: Help me to find this Sorry,i got this question from my friend and he couldn't find the answer. If the question change into: $\frac{8y^2+4xy^2}{2y+x} - \frac{x^3+2x^2y}{x+2y}= 2y+x$ What is the value of 6y?
 March 4th, 2014, 03:52 AM #6 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Re: Help me to find this Ok, then you have a quadratic in "y": (4x + 4)y^2 - (2x^2 + 4x)y - x^2 - x^3 = 0 Solve for y, then multiply by 6 since for some silly reason you're asking for value of 6y
 March 4th, 2014, 11:26 AM #7 Global Moderator   Joined: Dec 2006 Posts: 20,966 Thanks: 2216 Perhaps the friend got it written incorrectly. If the equation should have been $\frac{8y^2\,+\,4xy}{2y\,+\,x}\,-\,\frac{x^3\,+\,2x^2y}{x\,+\,2y}\,=\,2y\,+\,x,$ that simplifies to 4y - x² = 2y + x, so that 6y = 3x² + 3x.
March 4th, 2014, 04:31 PM   #8
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Re: Help me to find this

Quote:
 Originally Posted by naufalzhafran $\frac{8y^2+4xy^2}{2y+x} - \frac{x^3+2x^2y}{x+2y}= 2y+x$
Any reason for that "friend" of yours to write the equation that way?
Example:
x/d - y/d = d is simply x - y = d^2

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