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March 2nd, 2014, 06:54 PM   #1
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solve the following equation - Hard problem

I need to show all the work for extra credit.
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March 3rd, 2014, 05:31 AM   #2
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Re: solve the following equation - Hard problem

Your teacher said that if you showed someone else's work you would be given extra credit? That seems very strange.
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March 3rd, 2014, 12:23 PM   #3
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Re: solve the following equation - Hard problem

It is extremely difficult to solve an equation which is blank.
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March 4th, 2014, 11:35 AM   #4
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Re: solve the following equation - Hard problem

Here is the math problem
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March 4th, 2014, 11:47 AM   #5
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That equation has no real solutions. Are you sure it is given correctly?
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March 4th, 2014, 01:40 PM   #6
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Re: solve the following equation - Hard problem

I double check on the problem and Yes!
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March 4th, 2014, 04:18 PM   #7
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Re: solve the following equation - Hard problem

Well, you must mean "to the power"; then you get solutions:
http://www.wolframalpha.com/input/?i=so ... %3D0+for+x

The way you present your stuff, looks like multiplications.
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March 5th, 2014, 03:50 AM   #8
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After "double checking", a different equation was posted, so the original equation was incorrect.
It's easy to see that the second equation's real solutions correspond to sinx = 1/4 and sinx = 3/4, as the equation is effectively a quadratic equation in (16/81)^(sinx), solving which gives (16/81)^(sinx) = 2/3 or 8/27.
Hence x = ?/6 + k? or ?/3 + k?, where k is an integer.
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