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 March 2nd, 2014, 01:09 AM #1 Member   Joined: Nov 2011 Posts: 72 Thanks: 0 Solve Algebra How can (-2/(a)^1/2).(x+a)^3/2 be equal to (x+a)^1/2
 March 2nd, 2014, 01:25 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,746 Thanks: 2133 Did you intend three variables?
 March 2nd, 2014, 01:30 AM #3 Member   Joined: Nov 2011 Posts: 72 Thanks: 0 Re: Solve Algebra No. Its a Typo x and a are the only variables
 March 2nd, 2014, 01:56 AM #4 Global Moderator   Joined: Dec 2006 Posts: 20,746 Thanks: 2133 (-2/(a)^1/2).(x+a)^3/2 = (x+a)^1/2 leads to x = -a - (a^(1/2))/2.
 March 2nd, 2014, 02:16 AM #5 Member   Joined: Nov 2011 Posts: 72 Thanks: 0 Re: Solve Algebra I don't think you fully understood my question. I would like to solve (-2/(a^1/2)).(x+a)^3/2 to get (x+a)^1/2
 March 2nd, 2014, 06:42 AM #6 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,581 Thanks: 1038 Re: Solve Algebra Well then, ask your question properly. You should be asking WHEN does (-2/(a^1/2)).(x+a)^3/2 = (x+a)^1/2 And that happens when a = -x Would be nice if you used * for multiplication and bracket powers, like a^(1/2); a^1/2 means a divided by 2.
March 2nd, 2014, 06:59 AM   #7
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From: Lexington, MA

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Re: Solve Algebra

Hello, hatchelhoff!

Please check the statement of the problem.
As written, it makes no sense.

Quote:
 How can (-2/a^1/2).(x+a)^3/2 be equal to (x+a)^1/2

$\text{Those two expressions are equal if: }\:x \:=\:a\,-\,\frac{\sqrt{a}}{2}
\;\;\;\text{That is }how.$

Quote:
 I don't think you fully understood my question. I would like to solve (-2/(a^1/2)).(x+a)^3/2 to get (x+a)^1/2

Now you use the word "solve".
This means that we have an equation.[color=beige] .[/color](Where?)

$\text{W\!e have: }\:\left(\frac{-2}{a^{\frac{1}{2}}\right)(x\,+\,a)^{\frac{3}{2}}$
$\;\;\text{and you want to }simplify\text{ it to become: }\,(x\,+\,a)^{\frac{1}{2}}$

Sorry, it can't be done.

March 2nd, 2014, 08:40 AM   #8
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Joined: Dec 2006

Posts: 20,746
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Quote:
 Originally Posted by hatchelhoff I don't think you fully understood my question.
Although I could have added "or x = -a" to my previous post, your original request seems to be incorrectly formed from some related problem you were working on (but didn't post).

 March 3rd, 2014, 12:12 AM #9 Member   Joined: Nov 2011 Posts: 72 Thanks: 0 Re: Solve Algebra Thanks skipjack apologies for not realising that you had indeed answered the question I posed. I will try to create more accurate posts the next time. Thanks also sorban for explaining the error of my ways. Thanks Denis for highlighting that I could have posed my question better.
 March 3rd, 2014, 01:40 AM #10 Alicelewis Guest   Joined: Posts: n/a Thanks: Re: Solve Algebra Hello Everyone I am new in your topic and it's really interesting topic, one of my favorite, because I love algebraical question answer and knowledge about it. Here I found a site which help me out the all my problems in [link removed]. Last edited by CRGreathouse; April 1st, 2014 at 06:08 AM.

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