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March 1st, 2014, 03:29 AM   #1
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problem with simplification

3^2/(2.3^n) = 1/{2.3^(n-2)}
how did we do that?
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March 1st, 2014, 03:58 AM   #2
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Re: problem with simplification

Take an example where n = 6:



In general, the 3^2 on the top line cancels out 3^2 on the bottom, reducing the exponent on the bottom line from n to n-2:

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March 1st, 2014, 04:14 AM   #3
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Re: problem with simplification

I guess I am missing something here; where did 3^2 at the bottom came from or when we introduce it what law are we using?
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March 1st, 2014, 04:36 AM   #4
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Re: problem with simplification



Do you know how to do this calculation?
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March 1st, 2014, 05:43 AM   #5
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Re: problem with simplification

yes. same bases u add the exponents
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March 1st, 2014, 06:01 AM   #6
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Re: problem with simplification

So:

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March 1st, 2014, 06:04 AM   #7
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Re: problem with simplification

If we were to solve 9^x/ 3^(x-1)
I wud say 3^{2x -(x-1)} tel me if this is wrong?
Now 3^2/2.3^n if I say 3^(2 - n) am wrong how?
My question is when we divide and we have same bases we subtract top from bottom or bottom from top
To clarify this if we have 3^2 3^n which one is correct 3^(2-n) or 3^(n-2)
Jst confused bear with me
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March 1st, 2014, 06:17 AM   #8
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Re: problem with simplification

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March 1st, 2014, 06:58 AM   #9
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Re: problem with simplification

Hello, bongantedd!

Mystery solved!
Those are not decimal points . . . they are multiplications!



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