My Math Forum help me solve it :(

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 October 14th, 2008, 07:18 PM #1 Newbie   Joined: Oct 2008 Posts: 2 Thanks: 0 help me solve it :( solve: 1/2 [log12(x+4)squared]=2-log12(x-6)
October 15th, 2008, 01:02 PM   #2
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Re: help me solve it :(

Quote:
 Originally Posted by lilone solve: 1/2 [log12(x+4)squared]=2-log12(x-6)
Pu the log terms on one side of the equation. The use logx + logy = log(xy) to get log(something)=2. Next something = 144, where something is a polynomial in x. Solve.

 October 15th, 2008, 01:45 PM #3 Newbie   Joined: Oct 2008 Posts: 2 Thanks: 0 Re: help me solve it :( well thank you mathman i shall give it a go!

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