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March 1st, 2014, 06:33 AM   #11
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Re: Boys and some Sweets puzzle

That still looks kind of confusing. Always a different way to approach things though.
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March 1st, 2014, 07:11 AM   #12
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Re: Boys and some Sweets puzzle

Hello, Puzzled16!

I'll give it a try . . .


Quote:
Some boys share a bag of sweets.
(a) If each boy has 6 sweets, there will be 5 sweets left in the bag.
(b) If there were 3 more sweets in the bag, each boy could have exactly 7 sweets.
How many sweets were in the bag?







a)\;N \:=\:6(\,+\,5 \:=\:53" />

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March 6th, 2014, 02:12 PM   #13
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After 3 sweets are added to the five left in the bag, there are 8 in the bag, and these are just enough to let each boy have one more sweet, so there are 8 boys. Hence the bag originally held 8 6 + 5 = 53 sweets.
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March 6th, 2014, 04:05 PM   #14
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Re: Boys and some Sweets puzzle

Number of sweets = 6b + 5 = 7b -3 => b = 8 => Number of sweets = 6 x 8 + 5 = 7 * 8 - 3 = 53
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