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March 1st, 2014, 06:33 AM  #11 
Newbie Joined: Feb 2014 Posts: 12 Thanks: 0  Re: Boys and some Sweets puzzle
That still looks kind of confusing. Always a different way to approach things though.

March 1st, 2014, 07:11 AM  #12  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Re: Boys and some Sweets puzzle Hello, Puzzled16! I'll give it a try . . . Quote:
a)\;N \:=\:6(\,+\,5 \:=\:53" />  
March 6th, 2014, 02:12 PM  #13 
Global Moderator Joined: Dec 2006 Posts: 20,747 Thanks: 2133 
After 3 sweets are added to the five left in the bag, there are 8 in the bag, and these are just enough to let each boy have one more sweet, so there are 8 boys. Hence the bag originally held 8 × 6 + 5 = 53 sweets.

March 6th, 2014, 04:05 PM  #14 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,663 Thanks: 2643 Math Focus: Mainly analysis and algebra  Re: Boys and some Sweets puzzle
Number of sweets = 6b + 5 = 7b 3 => b = 8 => Number of sweets = 6 x 8 + 5 = 7 * 8  3 = 53


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