My Math Forum if sin(theta)= -.1234 find (theta) in [-4pi,pi]

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 February 21st, 2014, 09:19 AM #1 Newbie   Joined: Feb 2014 Posts: 1 Thanks: 0 if sin(theta)= -.1234 find (theta) in [-4pi,pi] If sin(theta)= -.1234, find all (theta) in [-4pi,pi] that make this equation true. What I have so far: sin is negative in QIII,QIV sin^-1(-.1234)=-.1237 0 - .1237 = -.1237 -pi + .1237 = -3.0179 -2pi - .1237 = -6.4069 -3pi + .1237 = -9.2011 There's nothing from 0 to pi, and from -3pi to -4pi since I need where sin is negative? Thanks for the help!
 February 21st, 2014, 11:35 AM #2 Math Team   Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 407 Re: if sin(theta)= -.1234 find (theta) in [-4pi,pi] Hello, mauro125! Correct! Good work!
 February 21st, 2014, 01:33 PM #3 Senior Member   Joined: Dec 2012 Posts: 372 Thanks: 2 Re: if sin(theta)= -.1234 find (theta) in [-4pi,pi] Hey there. You can also use the identity $sin(-\theta)= -sin(\theta)$ to view things a little clearer.
February 22nd, 2014, 04:57 PM   #4
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Quote:
 Originally Posted by mauro125 . . . -3pi + .1237 = -9.2011
Incorrect. -3pi + .1237 = -9.3011 (after rounding to four decimal places).

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