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February 17th, 2014, 08:39 PM   #1
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find max(a+b+c)




given :


if:

find:
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February 25th, 2014, 03:38 AM   #2
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Re: find max(a+b+c)

Just curious to know on the answer of this question..can someone help please.

Cheers,
Arun
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February 26th, 2014, 02:31 PM   #3
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It's an easy question. You're looking for (a, b, c) = (10, -1/2, -1).
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February 26th, 2014, 06:48 PM   #4
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Quote:
Originally Posted by skipjack
It's an easy question. You're looking for (a, b, c) = (10, -1/2, -1).
Thanks skipjack... could you please let me know how you arrive at the solution?
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February 26th, 2014, 07:28 PM   #5
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Re: find max(a+b+c)

I guess I'm missing something but it seems max(a + b + c) can be made arbitrarily large by choosing a arbitrarily large.
a = 11, b = (-55 - ?1705))/44, c = -20/(55 + ?1705) works and the sum a + b + c is just over 8.6.

I'm not sure what "if: k = min(a)" is about.
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February 27th, 2014, 01:06 AM   #6
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Obviously, "if: k = min(a)" isn't what was really meant. I assumed it was intended that a has its minimum value (which is 10), in which case, a + b + c has a maximum value (as only two values are possible).
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March 1st, 2014, 04:53 AM   #7
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Re: find max(a+b+c)

Quote:
Originally Posted by greg1313
I guess I'm missing something but it seems max(a + b + c) can be made arbitrarily large by choosing a arbitrarily large.
a = 11, b = (-55 - ?1705))/44, c = -20/(55 + ?1705) works and the sum a + b + c is just over 8.6.

I'm not sure what "if: k = min(a)" is about.
Greg, is there any method you used to arrive at the value of a=11.. is 8.6 the max of (a+b+c)..if you could give the steps, would be helpful. Thanks.
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March 1st, 2014, 09:21 AM   #8
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Re: find max(a+b+c)

Arun, why don't you send Abert Teng a PM...
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March 1st, 2014, 08:16 PM   #9
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Re: find max(a+b+c)

I chose a = 11. It's then possible to find values for b and c that fulfill the two given equations.
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March 3rd, 2014, 11:59 PM   #10
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Re: find max(a+b+c)

we know :


if :

then :

or:


put to(1)

we get :

so :

or :

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