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February 4th, 2014, 06:04 AM   #1
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Graph of function.

How to do part c?
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 February 4th, 2014, 07:48 AM #2 Math Team   Joined: Sep 2007 Posts: 2,409 Thanks: 6 Re: Graph of function. You are told that "the area of the shaded region is $y= 2x^2- 12x+ 48$" and asked to (i) "find the value of x given that the area of the shaded region is 52 sq cm" and (ii) "given that the area of the shaded region is 1.4". So you want to solve the equations $2x^2- 12x+ 48= 52$ and $2x^2- 12x+ 48= 1.4$. Subtracting 52 from both sides of the first equation you get $2x^2- 12x- 4= 0$ and then divide by 2 to get $x^2- 5x- 2= 0$. Solve that quadratic equation. The second equation is equivalent to $x^2- 6x+ 23.3= 0$. Solve by completing the square or by the quadratic formula.
 February 4th, 2014, 07:58 AM #3 Global Moderator   Joined: Dec 2006 Posts: 20,652 Thanks: 2085 (c)(i)  It would seem you are supposed to solve 2x˛ - 12x + 48 = 52. However, it appears from the diagram that the shaded area cannot exceed 48 cm˛. (c)(ii) You should be able to evaluate (2x˛ - 12x + 4 cm˛ for x = 1.4.

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