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February 3rd, 2014, 05:47 PM   #1
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An expression x^2 + (3y + 5)x + 2(y + 3)(y + 1)

In the expression x^2 + (3y + 5)x + 2(y + 3)(y + 1), what is the reason behind 2(y + 3) + (y + 1) = 3y + 5? What is the relationship between the coefficient of x, (3y + 5), and the three products 2(y + 3)(y + 1)?
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February 3rd, 2014, 08:51 PM   #2
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The correct equation is (y + 3) + 2(y + 1) = 3y + 5. That equation is clearly valid and explains why
x + (3y + 5)x + 2(y + 3)(y + 1) factorizes as (x + y + 3)(x + 2(y + 1)).
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