My Math Forum Solving roots

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 October 7th, 2008, 06:52 PM #1 Newbie   Joined: Feb 2008 Posts: 2 Thanks: 0 Solving roots I have a problem here. This is a homework were I have to solve the roots and order them from greatest to least. But specifically, my problem is with the roots greater than square. I have no idea how to solve them. I know how to solve square roots, but roots greater than square seem to have different way of solving, and I can't solve them. No idea. Can anyone please help me with these?
 October 7th, 2008, 08:44 PM #2 Senior Member   Joined: Jul 2008 Posts: 895 Thanks: 0 Re: Solving roots The order will be the same if you raise the power of each by the same amount. Express as fractional exponents first. I'll help with the first... $\sqrt 3 ,\sqrt[5]{2},\sqrt[{10}]{5}= 3^{{\textstyle{1 \over 2}}} ,2^{{\textstyle{1 \over 5}}} ,5^{{\textstyle{1 \over {10}}}}$ multiply by the LCD of the exponents. That would be 10. $3^{{\textstyle{{10} \over 2}}} ,2^{{\textstyle{{10} \over 5}}} ,5^{{\textstyle{{10} \over {10}}}}= 3^5 ,2^2 ,5^1$ Now it should be obvious.
 October 8th, 2008, 05:05 AM #3 Global Moderator   Joined: Dec 2006 Posts: 20,089 Thanks: 1902 Once you have converted a fifth root (for example) into an exponent of 1/5, just put 2^(1/5) (for example) into Google to find its value. Finally, order the resulting values.

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