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January 9th, 2014, 03:55 AM   #1
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Boolean Algebra

Hi there,

I have been stuck on this maths question for a long time, I do not know how to figure it out.
All I know is that I have to use Boolean algebra.

The Question is:

Prove, using Boolean algebra, that (A+B)(A+notB) = A.

I would really appreciate if someone could show me how to do this.

Thanks.
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January 9th, 2014, 07:21 AM   #2
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Using to denote NOT,
(A + B)(A + B) = AA + BA + AB + BB = A + A(B + B) + 0 = A + A1 = A + A = A.
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