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 January 9th, 2014, 03:55 AM #1 Newbie   Joined: Jan 2014 Posts: 1 Thanks: 0 Boolean Algebra Hi there, I have been stuck on this maths question for a long time, I do not know how to figure it out. All I know is that I have to use Boolean algebra. The Question is: Prove, using Boolean algebra, that (A+B)(A+notB) = A. I would really appreciate if someone could show me how to do this. Thanks.
 January 9th, 2014, 07:21 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,978 Thanks: 2229 Using ¬ to denote NOT, (A + B)·(A + ¬B) = A·A + B·A + A·¬B + B·¬B = A + A·(B + ¬B) + 0 = A + A·1 = A + A = A.

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