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 December 30th, 2013, 02:11 PM #1 Newbie   Joined: Dec 2013 Posts: 22 Thanks: 2 Help with an exponent question Evening, Question: (10^-1 + 10^-2)^-1 I've tried this a couple different ways, I'm sure I'm missing something simple. I know the answer is 100/11. If somebody could explain/show me the process to get to the correct answer it would be greatly appreciated Thanks, ~Lena
 December 30th, 2013, 03:05 PM #2 Newbie   Joined: Dec 2013 Posts: 22 Thanks: 2 Re: Help with an exponent question Pretty sure I figured it out. If this isn't correct, please correct me Just in case others weren't sure: = 1 / (10^-1 + 10^-2)^1 = 1/1 ÷ (1/10^1 + 1/10^2) = 1/1 ÷ (1/10 + 1/100) = 1/1 ÷ (11/100 + 1/100) = 1/1 ÷ 11/100 = 1/1 X 100/11 = 100/11 Thanks.
December 30th, 2013, 03:31 PM   #3
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Re: Help with an exponent question

Quote:
 Originally Posted by Kiphyl Pretty sure I figured it out. If this isn't correct, please correct me Just in case others weren't sure: = 1 / (10^-1 + 10^-2)^1 = 1/1 ÷ (1/10^1 + 1/10^2) = 1/1 ÷ (1/10 + 1/100) = 1/1 ÷ (11/100 + 1/100) = 1/1 ÷ 11/100 = 1/1 X 100/11 = 100/11 Thanks.
The 4th line above should read = 1/1 ÷ (10/100 + 1/100)

 December 30th, 2013, 03:40 PM #4 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,912 Thanks: 1110 Math Focus: Elementary mathematics and beyond Re: Help with an exponent question That's correct. Another way of doing it is $\frac{1}{\frac{1}{10}\,+\,\frac{1}{100}}\,\cdot\,\ frac{100}{100}\,=\,\frac{100}{10\,+\,1}\,=\,\frac{ 100}{11}$
 December 30th, 2013, 04:59 PM #5 Newbie   Joined: Dec 2013 Posts: 22 Thanks: 2 Re: Help with an exponent question Thanks
 December 31st, 2013, 12:09 AM #6 Global Moderator   Joined: Dec 2006 Posts: 20,263 Thanks: 1958 (10^-1 + 10^-2)^-1 = (.1 + .01)^-1 = .11^-1 = 100/11.

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