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December 30th, 2013, 01:11 PM   #1
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Help with an exponent question

Evening,

Question: (10^-1 + 10^-2)^-1

I've tried this a couple different ways, I'm sure I'm missing something simple. I know the answer is 100/11.

If somebody could explain/show me the process to get to the correct answer it would be greatly appreciated

Thanks,

~Lena
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December 30th, 2013, 02:05 PM   #2
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Re: Help with an exponent question

Pretty sure I figured it out. If this isn't correct, please correct me
Just in case others weren't sure:

= 1 / (10^-1 + 10^-2)^1
= 1/1 (1/10^1 + 1/10^2)
= 1/1 (1/10 + 1/100)
= 1/1 (11/100 + 1/100)
= 1/1 11/100
= 1/1 X 100/11
= 100/11

Thanks.
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December 30th, 2013, 02:31 PM   #3
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Re: Help with an exponent question

Quote:
Originally Posted by Kiphyl
Pretty sure I figured it out. If this isn't correct, please correct me
Just in case others weren't sure:

= 1 / (10^-1 + 10^-2)^1
= 1/1 (1/10^1 + 1/10^2)
= 1/1 (1/10 + 1/100)
= 1/1 (11/100 + 1/100)
= 1/1 11/100
= 1/1 X 100/11
= 100/11

Thanks.
The 4th line above should read = 1/1 (10/100 + 1/100)
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December 30th, 2013, 02:40 PM   #4
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Re: Help with an exponent question

That's correct. Another way of doing it is

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December 30th, 2013, 03:59 PM   #5
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Re: Help with an exponent question

Thanks
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December 30th, 2013, 11:09 PM   #6
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(10^-1 + 10^-2)^-1 = (.1 + .01)^-1 = .11^-1 = 100/11.
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