My Math Forum Algebra Problem

 Algebra Pre-Algebra and Basic Algebra Math Forum

 December 21st, 2013, 03:12 AM #1 Newbie   Joined: Dec 2013 Posts: 18 Thanks: 0 Algebra Problem A phone company offers two monthly charge plans. In Plan A, there is no monthly fee, but the customer pays 6 cents per minute of use. In Plan B, the customer pays a monthly fee of \$2 and then an additional 5 cent per minute of use. For what amounts of monthly phone use will Plan A cost more than Plan B? Use m for the number of minutes of phone use in a month, and solve your inequality for m. ?
 December 21st, 2013, 04:15 AM #2 Math Team   Joined: Apr 2010 Posts: 2,780 Thanks: 361 Re: Algebra Problem Let A(m) be the monthly charge for Plan A and Let B(m) be the monthly charge for plan B in dollars. Then A(m) = 0.06m B(m) = 0.05m + 2 We want A(m) > B(m), so solve 0.06m > 0.05m + 2 gives 0.01m > 2 i.e. m > 200 So if you call for more than 200 minutes (on average) then the charge of Plan A is higher.

 Tags algebra, problem

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Shocker Algebra 5 October 31st, 2013 10:47 AM najaa Algebra 4 May 13th, 2012 05:57 PM Grove77 Algebra 4 October 6th, 2009 03:02 PM empiricus Algebra 10 July 10th, 2009 01:50 PM sese Algebra 4 March 31st, 2009 06:18 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top