My Math Forum Help Rearranging an Equation

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 November 16th, 2013, 03:52 PM #1 Newbie   Joined: Nov 2013 Posts: 1 Thanks: 0 Help Rearranging an Equation Hi Guys, I have been trying to rearrange this equation, but I am having trouble with quarter fraction A = (4d/(p1-p2))^1/4 I would like to be able to rewrite the equation so it the subject is d I struggle with the 1/4, when or how to deal with it. Any help would be great, thanks very much.
November 16th, 2013, 04:29 PM   #2
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Re: Help Rearranging an Equation

Quote:
 Originally Posted by jwalker Hi Guys, I have been trying to rearrange this equation, but I am having trouble with quarter fraction A = (4d/(p1-p2))^1/4 I would like to be able to rewrite the equation so it the subject is d I struggle with the 1/4, when or how to deal with it. Any help would be great, thanks very much.
You can do it in 3 steps

1) Raise both sides to the 4th power

2) Multiply both sides by (p1 - p2)

3) Divide both sides by 4

Here's what it looks like

$A^4 \= \ $$$\frac{4d}{p_1 \ - \ p_2}$$^{ \cancel{\frac{1}{4}}}$^{ \cancel{ 4}}$

$A^4 \cdot (p_1 \ - \ p_2) \= \ \frac{4d}{ \cancel{ (p_1 \ - \ p_2)}} \ \cdot \ \cancel{ (p_1 \ - \ p_2)}$

$\frac{A^4 \cdot (p_1 \ - \ p_2)}{4} \= \ \frac{ \cancel{ 4}d}{ \cancel{ 4}}$

And we are done!

You can eliminate fractional exponents, like 1/4, by raising both sides of the equation to the RECIPROCAL power, in this case 4.

November 16th, 2013, 09:10 PM   #3
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Re: Help Rearranging an Equation

Quote:
 Originally Posted by jwalker A = (4d/(p1-p2))^1/4
Let k = p1-p2 (easier to "handle")

A = (4d / k)^(1/4)
A^4 = 4d / k
4d = kA^4
d = kA^4 / 4

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