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October 28th, 2013, 02:57 AM   #1
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maximum value

If a,b are natural numbers such that then the maximum possible value of ab is
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October 28th, 2013, 03:31 AM   #2
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Re: maximum value

Here is an 'intuitive' approach. The difference between consecutive integer squares is in arithmetic progression of the odd integers.


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So we want 2n + 1 = 2013 which makes n = 1006



ab = 1006*1007 = 1013042

This is the maximum since it gives









WE can't do better than that because there are no integer squares between consecutive integer squares.

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November 8th, 2013, 02:29 AM   #3
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Re: maximum value

Can you tell what will be the minimum value?
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