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October 25th, 2013, 04:49 PM   #1
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Logarithms question

p, q > 0

(log b_p q) + (log b_q p) = 5/2

pq = 54sqrt2

What is (p+q) /3?

Can anyone give me pointers on where to start?
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October 25th, 2013, 05:57 PM   #2
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Re: Logarithms question

The notation is confusing. What is the base of each logarithm and what is the argument of each logarithm?
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October 25th, 2013, 06:21 PM   #3
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Re: Logarithms question

Hello, cube198!

I think I understand what you are saying . . .


Quote:







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October 26th, 2013, 02:27 AM   #4
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Either way, (p + q)/3 = 6 + ?2.
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October 26th, 2013, 07:45 AM   #5
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Re: Logarithms question

Thank you very much to everyone that helped!
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