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October 12th, 2013, 02:06 AM  #1 
Senior Member Joined: Oct 2009 Posts: 895 Thanks: 1  A box contains 3 white, 8 red, 9 blue
Hi 1) A box contains 3 white, 8 red, 9 blue balls. If 3 balls are selected at random, find the probability A) one ball of the each colour is selected B) all balls are of the same colour C) one red and two of any colour D) All 3 are red E) at least 1 is white F) the balls are drawn in the order red, white, blue. H) Two Balls are red 2) A box contain 4 bad 6 good tubes. Two are drawn from the box at a time. What is the probability A) that both the tubes drawn are good? B) one is good and other is bad? 
October 12th, 2013, 03:49 AM  #2 
Senior Member Joined: Feb 2013 Posts: 281 Thanks: 0  Re: A box contains 3 white, 8 red, 9 blue
I elaborate you the 2B, the others are similar. definition of the probability in general:

October 12th, 2013, 05:12 AM  #3 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,155 Thanks: 466 Math Focus: Calculus/ODEs  Re: A box contains 3 white, 8 red, 9 blue
For the first question, let's begin with part A). How many ways are there to draw one ball of each color? How many ways are there in total to choose 3 balls from the total of 20? 
October 12th, 2013, 01:54 PM  #4 
Global Moderator Joined: Dec 2006 Posts: 18,841 Thanks: 1564 
2(A) In this earlier topic, the probability that both tubes drawn are good was found to be 1/3. 2(B) Similarly, the probability that both tubes drawn are bad is 2/15, so the required probability is 1  1/3  2/15 = 8/15. 

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