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October 5th, 2013, 11:03 PM  #1 
Member Joined: Aug 2013 Posts: 69 Thanks: 0  translating a circle
Hi, I want to translate y = sqrt.(5xx^2) down 2 and to the left 7. Putting the above equation into standard form, I get y^2 +(x5/2)^2 = 25/4 (y+2)^2 +(x+9/2)^2= 25/4 How do I get this into y=x form? Brain is dead :+} 
October 6th, 2013, 04:18 AM  #2  
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,943 Thanks: 1132 Math Focus: Elementary mathematics and beyond  Re: translating a circle Quote:
 
October 6th, 2013, 10:54 AM  #3 
Member Joined: Aug 2013 Posts: 69 Thanks: 0  Re: translating a circle
Can you show me the steps? And I this circle translated 7 from the original point, so iy is @ 4.5=x 
October 6th, 2013, 02:36 PM  #4 
Global Moderator Joined: Dec 2006 Posts: 20,746 Thanks: 2133 
Translating y = f(x) down by 2 and to the left by 7 gives y = f(x + 7)  2.

October 7th, 2013, 06:53 AM  #5  
Math Team Joined: Sep 2007 Posts: 2,409 Thanks: 6  Re: translating a circle Quote:
Subtract from both sides: Take the square root of both sides: Subtract 2 from both sides: You can, if you want, multiply out that to get inside the square root.  

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