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October 5th, 2013, 11:03 PM   #1
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translating a circle

Hi,

I want to translate y = sqrt.(5x-x^2)

down 2 and to the left 7.

Putting the above equation into standard form, I get
y^2 +(x-5/2)^2 = 25/4

(y+2)^2 +(x+9/2)^2= 25/4

How do I get this into y=x form?

Brain is dead :+}
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October 6th, 2013, 04:18 AM   #2
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Re: translating a circle

Quote:
Originally Posted by yogazen2013
I want to translate y = sqrt.(5x-x^2)

down 2 and to the left 7.
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October 6th, 2013, 10:54 AM   #3
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Re: translating a circle

Can you show me the steps?

And I this circle translated 7 from the original point, so iy is @ -4.5=x
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October 6th, 2013, 02:36 PM   #4
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Translating y = f(x) down by 2 and to the left by 7 gives y = f(x + 7) - 2.
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October 7th, 2013, 06:53 AM   #5
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Re: translating a circle

Quote:
Originally Posted by yogazen2013
Can you show me the steps?

And I this circle translated 7 from the original point, so iy is @ -4.5=x
Solve the equation for y.

Subtract from both sides:


Take the square root of both sides:


Subtract 2 from both sides:


You can, if you want, multiply out that to get inside the square root.
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