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September 15th, 2008, 04:51 PM   #1
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Mixture Problem, please help

Question is:

Brine is a solution of salt and water. If a tub contains 50 lbs of a 5% solution of brine, how much water must evaporate to change it to an 8% solution?

Thank you in advance for your help in showing me step by step.

Horizont
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September 16th, 2008, 04:12 AM   #2
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Re: Mixture Problem, please help

How much salt would be in 50lb of a 5% solution? How much water?

With that much salt, how much water do you need for an 8% solution?

Calculate the difference.
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September 16th, 2008, 04:15 AM   #3
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Original mass - new mass = 50lb - (5%/8%)50lb = 18żlb.
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September 16th, 2008, 10:12 AM   #4
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Re: Mixture Problem, please help

This is interesting. I was just in conversation in another forum about the merits of directing someone to a solution vs simply doing it for them. OK, I give up, It's like trying to get someone to quit smoking. They have good reasons [to them] for not doing so. That's their choice, I suppose.
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