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September 18th, 2013, 11:45 AM   #1
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subtract,add,multiply,divide and get the same result

Hello there am having a little problem on solving this :S, I have four numbers given when by collecting them I get the 68 (for example), then I need to add for example 3 to one of them, -3 to the other, *3 the other and \3 to the other... something like this .. the opponent should not be repeated twice (X1-3)+(X2*3)+(X3-3)+(X4\3) and give 68 ...

Examples:

(X1 - 3) + (X2 + 3) + (X3 : 3) + (X3 * 3) = (not 68)
(X1 * 3) + (X2 - 3) + (X3 + 3) + (X3 : 3) = (not 68)
(X1 + 3) + (X2 : 3) + (X3 - 3) + (X4 * 3) = 68 :)
I'd really appreciate your help!!

Last edited by greg1313; May 17th, 2018 at 04:32 AM.
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September 18th, 2013, 11:46 AM   #2
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Re: subtract,add,multiply,divide and get the same result

So whatever I do I should get always 68 !!!! Is there a formula I can work on ??? (sorry forget to mention)
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September 18th, 2013, 08:00 PM   #3
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a + d/c + b - d/c + c*(d/c) + d/(d/c) = a + b + c + d or (trivially) use 1 instead of d/c.
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