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August 4th, 2013, 09:22 PM   #1
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Alpha/Beta and Beta/Alpha (quadratic roots)

If Alpha and Beta be the roots of the equation 2x^2-6x+5=0 , find the equation whose roots are:
I know they both are symmetric.

a= 2 , b=-6 and c=5.

alpha+beta = -6/2 and alpha*beta = 5/2. How to use them? I am confused again.. I am not getting how to get the next step. Besides I don't have proper book... the text book I have is full of errors and they call it a self-teaching guide. :/
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August 4th, 2013, 10:39 PM   #2
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Re: Alpha/Beta and Beta/Alpha (quadratic roots)

Quote:
Originally Posted by Dean1884
If Alpha and Beta be the roots of the equation 2x^2-6x+5=0 , find the equation whose roots are:
I know they both are symmetric.

a= 2 , b=-6 and c=5.

alpha+beta = -6/2 and alpha*beta = 5/2. how to use them ? I am confused again.. I am not getting how to get the next step. Besides I don't have proper book.. the text book I have is full of errors and they call it a self-teaching guide. :/
Hello!
; ; ; ; and ........
Thank You!
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August 5th, 2013, 02:30 AM   #3
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Re: Alpha/Beta and Beta/Alpha (quadratic roots)

Thanks Dacu. The book says the answer is 5x^2-8x+5 = 0. How to turn and into this form ? What should I do in such situations?
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August 5th, 2013, 03:59 AM   #4
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Re: Alpha/Beta and Beta/Alpha (quadratic roots)

Quote:
Originally Posted by Dean1884
Thanks Dacu. The book says the answer is 5x^2-8x+5 = 0. How to turn and into this form ? What should I do in such situations?
; ; and so the equation is and it is equivalent to the equation .
Thank you!
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August 5th, 2013, 08:03 AM   #5
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Quote:
Originally Posted by Dean1884
alpha+beta = -6/2 and alpha*beta = 5/2. How to use them?
How to turn and into this form ?
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August 5th, 2013, 12:16 PM   #6
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Re: Alpha/Beta and Beta/Alpha (quadratic roots)

oh ok. thanks.
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August 5th, 2013, 12:35 PM   #7
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If copying from your initial attempt, note that is 6/2, not -6/2.
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August 5th, 2013, 12:45 PM   #8
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Re: Alpha/Beta and Beta/Alpha (quadratic roots)

all right.
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