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August 4th, 2013, 09:22 PM  #1 
Member Joined: Jul 2013 Posts: 58 Thanks: 0  Alpha/Beta and Beta/Alpha (quadratic roots)
If Alpha and Beta be the roots of the equation 2x^26x+5=0 , find the equation whose roots are: I know they both are symmetric. a= 2 , b=6 and c=5. alpha+beta = 6/2 and alpha*beta = 5/2. How to use them? I am confused again.. I am not getting how to get the next step. Besides I don't have proper book... the text book I have is full of errors and they call it a selfteaching guide. :/ 
August 4th, 2013, 10:39 PM  #2  
Senior Member Joined: Apr 2013 Posts: 425 Thanks: 24  Re: Alpha/Beta and Beta/Alpha (quadratic roots) Quote:
; ; ; ; and ........ Thank You!  
August 5th, 2013, 02:30 AM  #3 
Member Joined: Jul 2013 Posts: 58 Thanks: 0  Re: Alpha/Beta and Beta/Alpha (quadratic roots)
Thanks Dacu. The book says the answer is 5x^28x+5 = 0. How to turn and into this form ? What should I do in such situations?

August 5th, 2013, 03:59 AM  #4  
Senior Member Joined: Apr 2013 Posts: 425 Thanks: 24  Re: Alpha/Beta and Beta/Alpha (quadratic roots) Quote:
Thank you!  
August 5th, 2013, 08:03 AM  #5  
Global Moderator Joined: Dec 2006 Posts: 20,381 Thanks: 2011  Quote:
 
August 5th, 2013, 12:16 PM  #6 
Member Joined: Jul 2013 Posts: 58 Thanks: 0  Re: Alpha/Beta and Beta/Alpha (quadratic roots)
oh ok. thanks.

August 5th, 2013, 12:35 PM  #7 
Global Moderator Joined: Dec 2006 Posts: 20,381 Thanks: 2011 
If copying from your initial attempt, note that is 6/2, not 6/2.

August 5th, 2013, 12:45 PM  #8 
Member Joined: Jul 2013 Posts: 58 Thanks: 0  Re: Alpha/Beta and Beta/Alpha (quadratic roots)
all right. 

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