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July 29th, 2013, 02:30 PM   #1
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How to get rid of a negative exponent on logs...

Hi,

I've hit a brick wall here...not sure how to proceed

Some insight on the original function: ln(x)=log4(x+3)-log4(x-2)

Now solve for Ln(1/2)
therefore.... Ln(1/2)= Log4(1/2+3)-Log4(1/2-2)
= Log4((7/2)/(-3/2))
= Log4(-7/3)....now what? i know i have to apply the natural log at this point, but why? how? i don't understand...HELP!!!
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July 29th, 2013, 05:41 PM   #2
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Re: How to get rid of a negative exponent on logs...

Hello, Toyboy!

Please give us the original wording of the problem.
What you presented makes little sense.


Quote:


[color=beige] . [/color][color=blue]This can't be right![/color]

[color=beige] . [/color][color=blue]Are you SURE that's what it says?[/color]










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July 30th, 2013, 02:52 AM   #3
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Re: How to get rid of a negative exponent on logs...

Hi Soroban,

My apologies, attached is a pciture of the actual question....
Attached Images
File Type: jpg 20130730_123901.jpg (48.6 KB, 160 views)
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July 30th, 2013, 03:01 AM   #4
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Re: How to get rid of a negative exponent on logs...

This is what you should be doing:
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July 30th, 2013, 04:16 AM   #5
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Re: How to get rid of a negative exponent on logs...

Quote:
Originally Posted by gelatine1
This is what you should be doing:
Thanks alot man, don't know what i was thinking....i could almost slap myself
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