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June 16th, 2013, 02:09 PM   #1
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Equation with 3 radicals

Hi I'm having an issue when it comes to solving this equation.

?(x + 2) + ?(x - 3) = ?(3x - 4)

I start by squaring, but I don't really know how to multiply 2 radical binomials, ?(x +2) * ?(x - 3) and I can't find any information about it.
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June 16th, 2013, 03:08 PM   #2
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Re: Equation with 3 radicals

You can use the property .

You will obviously have to square two times, and then you'll want to make sure no extraneous solutions were introduced, so check ALL of the solutions you obtain in the original equation by substitution.
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June 16th, 2013, 03:47 PM   #3
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Quote:
Originally Posted by Engasaurus
I can't find any information about it.
You don't need any information about it. What have you got so far?
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June 16th, 2013, 05:06 PM   #4
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Re: Equation with 3 radicals

Quote:
Originally Posted by Engasaurus
?(x + 2) + ?(x - 3) = ?(3x - 4)
a = x + 2, b = x - 3, c = 3x - 4

"squaring twice" means: 4ab = (c - a - b)^2
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