My Math Forum Equation with 3 radicals

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 June 16th, 2013, 02:09 PM #1 Newbie   Joined: Apr 2013 Posts: 5 Thanks: 0 Equation with 3 radicals Hi I'm having an issue when it comes to solving this equation. ?(x + 2) + ?(x - 3) = ?(3x - 4) I start by squaring, but I don't really know how to multiply 2 radical binomials, ?(x +2) * ?(x - 3) and I can't find any information about it.
 June 16th, 2013, 03:08 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Equation with 3 radicals You can use the property $\sqrt{a}\cdot\sqrt{b}=\sqrt{ab}$. You will obviously have to square two times, and then you'll want to make sure no extraneous solutions were introduced, so check ALL of the solutions you obtain in the original equation by substitution.
June 16th, 2013, 03:47 PM   #3
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Quote:
 Originally Posted by Engasaurus I can't find any information about it.
You don't need any information about it. What have you got so far?

June 16th, 2013, 05:06 PM   #4
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Quote:
 Originally Posted by Engasaurus ?(x + 2) + ?(x - 3) = ?(3x - 4)
a = x + 2, b = x - 3, c = 3x - 4

"squaring twice" means: 4ab = (c - a - b)^2

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