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June 12th, 2013, 09:57 AM   #1
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Partial Fraction help!

I hate Maths

Just to clarify my position on the subject.

down to business! I have this partial fraction, which I am told is different from ones I am used to, as Instead of using A and B, we also use C to solve this question! how good.

here is problem

3x^3-2x^2-16x+20
----------------------
(x-2)(x+2)
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June 12th, 2013, 10:50 AM   #2
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Re: Partial Fraction help!

You may have misunderstood. You do not need a third constant on a fraction, but since the numerator has degree 3 while the denominator has degree 2, you should first divide to get a "mixed fraction" rather than an "improper fraction".


Now there exist constants A and B such that .
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June 12th, 2013, 11:53 AM   #3
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Re: Partial Fraction help!

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June 12th, 2013, 08:48 PM   #4
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True, but you started with an extra "3" in the numerator.
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June 13th, 2013, 12:38 AM   #5
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Re: Partial Fraction help!

To what are you referring?
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June 13th, 2013, 08:05 AM   #6
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Sorry, I should have been saying that [color=#00AA00]HallsofIvy[/color] omitted the leading "3" from the numerator of the fraction.
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