My Math Forum Simplification problem

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 June 10th, 2013, 11:51 PM #1 Newbie   Joined: Jun 2013 Posts: 1 Thanks: 0 Simplification problem Can anyone help me with this question please? I really can't find a way to solve it. All help will be very very appreciated! (2^n+2) + (2^n-4) The answer is 2^n-4 (65)... HOW? :'( PLEASE HELP
 June 11th, 2013, 12:03 AM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Simplification problem I split your post from the topic onto which you tagged it. It is best that you create your own topics for your questions. Your question is unclear. As written is appears the sum is $2^{n+1}-2=2(2^n-1)$ What does the (65) represent?
 June 11th, 2013, 12:06 AM #3 Math Team   Joined: Apr 2010 Posts: 2,780 Thanks: 361 Re: Simplification problem Was "solve 2^(n+2) + 2^(n-4) = 65 for n" intended?
 June 11th, 2013, 06:13 AM #4 Math Team     Joined: May 2013 From: The Astral plane Posts: 2,258 Thanks: 929 Math Focus: Wibbly wobbly timey-wimey stuff. Re: Simplification problem Perhaps it is Simplify $2^{n + 2} + 2^{n - 4}$ That gives the OP's answer. -Dan
 June 11th, 2013, 08:51 AM #5 Global Moderator   Joined: Dec 2006 Posts: 20,941 Thanks: 2210 Because $2^{n\small + 2}\,+\,2^{n\small - 4}\,=\,2^62^{n\small - 4}\,+\,2^{n\small - 4}\,=\,(2^{\small6}\,+\,1)2^{n\small - 4}\,=\,2^{n\small - 4}(65).$

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