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June 7th, 2013, 01:19 AM   #1
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impossible (prove that 0 = 1)

Can you solve that 0=1 by using at least two different methods?
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June 7th, 2013, 02:18 AM   #2
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Re: imposible

0*0 = 0*1
Divide by 0. Gives
0 = 1.

Like this, many ways can be found.
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June 7th, 2013, 08:37 AM   #3
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Re: imposible





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June 7th, 2013, 11:32 AM   #4
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Re: impossible (prove that 0 = 1)

Don'tcha just hate explaining why that last one is wrong?

-Dan
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June 7th, 2013, 03:25 PM   #5
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Re: impossible (prove that 0 = 1)

So interesting with the solution of two of you. I have just found another way to show that 0=1.
lim(x->0) of (2013/x +1) =lim(x->0) of (2013/x) +1= indefinite +1=indefinite
Then, simplify indefinite we obtain 1=0.
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June 7th, 2013, 09:11 PM   #6
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Re: impossible (prove that 0 = 1)

Suppose it is not clear what sqrt(1) is, consider...









So even if is defined as +1 , you still get

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June 9th, 2013, 02:24 AM   #7
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Re: impossible (prove that 0 = 1)

0 = 1 In the trivial ring.

http://mathworld.wolfram.com/TrivialRing.html

http://en.m.wikipedia.org/wiki/Trivial_ring

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June 9th, 2013, 04:28 AM   #8
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Re: impossible (prove that 0 = 1)

Quote:
Originally Posted by agentredlum
0 = 1 In the trivial ring.
Best answer of all, you rule
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June 9th, 2013, 05:18 AM   #9
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Re: impossible (prove that 0 = 1)

























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June 9th, 2013, 07:22 AM   #10
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Re: impossible (prove that 0 = 1)

If a hockey game ends 0-0, then overtime is played until 1-0;
the loser gets 1 point in the standings, so 0 = 1
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