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June 10th, 2013, 02:42 AM  #11 
Newbie Joined: Jan 2010 Posts: 20 Thanks: 0  Re: impossible (prove that 0 = 1)
Hoempa you can't divide by 0. Its not defined. Soroban,In third step,?a * ?b is not equal to ?ab. Hence, ?1 can't be split into ?1 * ?1. KyVancchay, I didn't get how you simplify the indefinite. Soroban,your Maclaurin series is wrong. ln(1+x) = x  x^2/2! +x^3/3! x^4/4! + ...... 
June 10th, 2013, 02:51 AM  #12  
Math Team Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233  Re: impossible (prove that 0 = 1) Quote:
The winner get's 2 points in the standings so 1 = 2 :P  
June 10th, 2013, 02:58 AM  #13  
Math Team Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233  Re: impossible (prove that 0 = 1) Quote:
 
June 11th, 2013, 07:04 AM  #14 
Member Joined: May 2013 From: Phnom Penh, Cambodia Posts: 77 Thanks: 0  Re: impossible (prove that 0 = 1)
Another way to solve that 1=0. Suppose that we have a=b, then a^2 =ab a^2 b^2 =ab b^2 (ab)(a+b)=b(ab) a+b=b 2b=b b=0 b=0*b 1=0 
June 11th, 2013, 07:22 AM  #15 
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361  Re: impossible (prove that 0 = 1) so 1= 1. Add 1 and divide by 2 to get 0 = 1.

June 11th, 2013, 07:24 AM  #16 
Member Joined: May 2013 From: Phnom Penh, Cambodia Posts: 77 Thanks: 0  Re: impossible (prove that 0 = 1)
0! =1!, then 0=1

June 11th, 2013, 10:26 PM  #17  
Math Team Joined: Mar 2012 From: India, West Bengal Posts: 3,871 Thanks: 86 Math Focus: Number Theory  Re: impossible (prove that 0 = 1) Quote:
 

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