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May 21st, 2013, 03:16 PM   #1
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Area problem

Theres one small square with an area of 5, and one large square with an area of 125. the Problem asks for how many yards of fencing are needed to enclose the two squares.
I thought the answer would be 104 to the sq.root of 5, but thats wrong.
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May 21st, 2013, 03:37 PM   #2
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Re: Area problem

How are the squares orientated to each other? For example like in 1 or in 2?

(image not to scale)
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May 21st, 2013, 04:34 PM   #3
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Re: Area problem

like figure 2
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May 21st, 2013, 05:06 PM   #4
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Re: Area problem

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May 21st, 2013, 05:32 PM   #5
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Re: Area problem

I believe you mean 24 sqrt5, but how do you get 20? I divided 125 by 5 = 25sqrt5. and 4x25=100sqrt for perimeter, which is wrong, and I'm wondering why/ how to get 20 as perimeter or 5 as side?
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May 21st, 2013, 05:57 PM   #6
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Re: Area problem

Nevermind, I figured out why its not 100. Thank you for the replies, appreciate it.
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May 22nd, 2013, 01:46 AM   #7
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Re: Area problem

I'd go to the teacher and tell it can be done with less
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May 22nd, 2013, 03:36 AM   #8
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Re: Area problem

Quote:
Originally Posted by Imaxium
Theres one small square with an area of 5, and one large square with an area of 125. the Problem asks for how many yards of fencing are needed to enclose the two squares.
I thought the answer would be 104 to the sq.root of 5, but thats wrong.
Hello!
I do not understand!What are the relative positions of the two squares?
Thank You!
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May 22nd, 2013, 05:12 AM   #9
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Re: Area problem

Quote:
Originally Posted by Dacu
Hello!
I do not understand!What are the relative positions of the two squares?
Thank You!
[color=#000000]If you are talking about Hoempa's beautiful figure, it gives two possible relative positions. The first one describes the small square inside the bigger one, placed in the corner, in order for its two sides to be covered by the fence of the bigger square (we need less material by using this way). [/color]
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