May 21st, 2013, 02:16 PM  #1 
Newbie Joined: May 2013 Posts: 24 Thanks: 0  Area problem
Theres one small square with an area of 5, and one large square with an area of 125. the Problem asks for how many yards of fencing are needed to enclose the two squares. I thought the answer would be 104 to the sq.root of 5, but thats wrong. 
May 21st, 2013, 02:37 PM  #2 
Math Team Joined: Apr 2010 Posts: 2,778 Thanks: 361  Re: Area problem
How are the squares orientated to each other? For example like in 1 or in 2? (image not to scale) 
May 21st, 2013, 03:34 PM  #3 
Newbie Joined: May 2013 Posts: 24 Thanks: 0  Re: Area problem
like figure 2

May 21st, 2013, 04:06 PM  #4 
Math Team Joined: Nov 2010 From: Greece, Thessaloniki Posts: 1,989 Thanks: 133 Math Focus: pre pre pre pre pre pre pre pre pre pre pre pre calculus  Re: Area problem 
May 21st, 2013, 04:32 PM  #5 
Newbie Joined: May 2013 Posts: 24 Thanks: 0  Re: Area problem
I believe you mean 24 sqrt5, but how do you get 20? I divided 125 by 5 = 25sqrt5. and 4x25=100sqrt for perimeter, which is wrong, and I'm wondering why/ how to get 20 as perimeter or 5 as side?

May 21st, 2013, 04:57 PM  #6 
Newbie Joined: May 2013 Posts: 24 Thanks: 0  Re: Area problem
Nevermind, I figured out why its not 100. Thank you for the replies, appreciate it.

May 22nd, 2013, 12:46 AM  #7 
Math Team Joined: Apr 2010 Posts: 2,778 Thanks: 361  Re: Area problem
I'd go to the teacher and tell it can be done with less 
May 22nd, 2013, 02:36 AM  #8  
Senior Member Joined: Apr 2013 Posts: 425 Thanks: 24  Re: Area problem Quote:
I do not understand!What are the relative positions of the two squares? Thank You!  
May 22nd, 2013, 04:12 AM  #9  
Math Team Joined: Nov 2010 From: Greece, Thessaloniki Posts: 1,989 Thanks: 133 Math Focus: pre pre pre pre pre pre pre pre pre pre pre pre calculus  Re: Area problem Quote:
 

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