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April 27th, 2013, 09:09 PM  #1 
Member Joined: Mar 2013 Posts: 36 Thanks: 0  Algebra simplification
Hi! I am unsure of the intermediate steps in these equations: 1. When I multiply through by 1, the equations don't remain equal. What's the intermediate step? 2. My simplification gives: 
April 28th, 2013, 04:28 AM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,957 Thanks: 1146 Math Focus: Elementary mathematics and beyond  Re: Algebra simplification
1. If you mean , multiply through by 3. 2. 
April 28th, 2013, 04:44 AM  #3  
Global Moderator Joined: Dec 2006 Posts: 20,916 Thanks: 2199  Quote:
 
April 28th, 2013, 02:41 PM  #4  
Member Joined: Mar 2013 Posts: 36 Thanks: 0  Re: Algebra simplification
Thank you. Quote:
[/quote]2. [/quote] I just realized that the two (2) is a shared denominator.  
April 28th, 2013, 02:45 PM  #5  
Member Joined: Mar 2013 Posts: 36 Thanks: 0  Quote:
I multiply by 1 to remove the negative before the parentheses: By the way, why is it that multiplying through by 1 doesn't change the sign inside the parentheses:  
April 28th, 2013, 03:10 PM  #6 
Global Moderator Joined: Dec 2006 Posts: 20,916 Thanks: 2199 
The exponentiation would need to be done first, and then the multiplication by 1 could be done by changing the sign of each term within the parentheses, not just the second term within the parentheses. (x  3)² = (x²  6x + 9) = x² + 6x  9 

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