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July 27th, 2008, 04:52 PM   #1
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never mind - i got it

edit : nvm i got it, i should have got it earlier >_>

[ sin(a)cos(b) + sin(b)cos(a) ] / cos(a)cos{b) = tan(a) + tan(b)

What I don't understand is how the left side equals tan(a) + tan(b). Right now, I'm stuck on left side equals tan(a)tan(b) + tan(b)tan(a). Thanks for reading .
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July 30th, 2008, 05:37 AM   #2
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Assuming cos(a) and cos(b) are both non-zero,
sin(a)cos(b) + sin(b)cos(a) ] / (cos(a)cos{b)) = (sin(a)/cos(a))(cos(b)/cos(b)) + (sin(b)/cos(b))(cos(a)/cos(a)) = tan(a) + tan(b).
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