My Math Forum never mind - i got it

 Algebra Pre-Algebra and Basic Algebra Math Forum

 July 27th, 2008, 04:52 PM #1 Newbie   Joined: Jul 2008 Posts: 6 Thanks: 0 never mind - i got it edit : nvm i got it, i should have got it earlier >_> [ sin(a)cos(b) + sin(b)cos(a) ] / cos(a)cos{b) = tan(a) + tan(b) What I don't understand is how the left side equals tan(a) + tan(b). Right now, I'm stuck on left side equals tan(a)tan(b) + tan(b)tan(a). Thanks for reading .
 July 30th, 2008, 05:37 AM #2 Global Moderator   Joined: Dec 2006 Posts: 17,211 Thanks: 1291 Assuming cos(a) and cos(b) are both non-zero, sin(a)cos(b) + sin(b)cos(a) ] / (cos(a)cos{b)) = (sin(a)/cos(a))(cos(b)/cos(b)) + (sin(b)/cos(b))(cos(a)/cos(a)) = tan(a) + tan(b).

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