My Math Forum Prove ABA' is singular

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 October 19th, 2019, 06:02 PM #1 Newbie   Joined: Oct 2019 From: Taiwan Posts: 2 Thanks: 0 Prove ABA' is singular A is MxN matrix. B is NxN matrix. If N
 October 19th, 2019, 11:16 PM #2 Senior Member     Joined: Oct 2018 From: USA Posts: 102 Thanks: 77 Math Focus: Algebraic Geometry We know that $A$ is $m \times n$ and $B$ is $n \times n$, so $AB$ is $m \times n$ and $ABA^{t}$ is $m \times m$. Since \$n
 October 20th, 2019, 12:50 AM #3 Newbie   Joined: Oct 2019 From: Taiwan Posts: 2 Thanks: 0 Thank you!! Very clear.

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