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 October 7th, 2019, 11:41 AM #1 Newbie   Joined: Sep 2019 From: Canada Posts: 2 Thanks: 0 Math Focus: Algebra Help turning word problems into equations please... Hello, my class has just started exploring rational equations. I have no problem solving the equations on their own but when I need to convert information into these equations I can confuse myself. If anyone can help me with turning these two problems into rational equations, I'd be really grateful! 1. A school purchases a load of t-shirts with their emblem for \$450. They then put aside two t-shirts, and sell the rest for \$560, at \$10 per shirt. How many shirts were in the initial shipment? 2. Two boys are walking for 30km. Boy-A walks at a pace 1.4km/h faster then Boy-B. Boy-A stops during his walk to talk with a friend for 20min, however, he still completes the 30km walk 2hrs before Boy-B. How long did they each take to complete the walk? Thank you for your help ! Last edited by SimpleMinded; October 7th, 2019 at 12:26 PM.  October 7th, 2019, 11:58 AM #2 Senior Member Joined: Jun 2019 From: USA Posts: 310 Thanks: 162 Note: Put a backslash before your dollar signs (\\$). The forum uses dollar signs as a tag for LaTeX code. 1. Let N be the number of t-shirts ordered. You are told two things: (a) A school purchases a load of t-shirts with their emblem for \$450. Equation:$Buying~cost = \$450$ Implied equation: $\$450 = N\cdot (buying~cost~per~shirt)$(b) Then, they put aside two t-shirts and sell the rest for \$560, \$10 per shirt. Equation:$(N-2~shirts)\cdot (\$10/shirt) = \$560$(a) is irrelevant, (b) allows you to find N. 2. "Two boys are walking for 30km." Let$L = 30~km$be the distance travelled. "Boy-A walks at a pace 1.4km/h faster then Boy-B." Let$V_A$and$V_B$be their respective speeds. Then$V_A = V_B + 1.4~ km/hr$. "Boy-A stops during his walk to talk with a friend for 20min" Let$t_A$and$t_B$be the time Boy A takes and the time Boy B takes to walk the 30 km. Time is length/speed, so$\displaystyle t_A = \frac{L}{V_A} + \frac{1}{3} hr$. (Note I changed to hours to make the units consistent.) Assume Boy-B doesn't stop,$\displaystyle t_B = \frac{L}{V_B}$. "[Boy-A] still completes the 30km walk 2hrs before Boy-B."$t_A = t_B - 2~hr\$ I hope this helps. Thanks from SimpleMinded

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