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October 7th, 2019, 11:41 AM  #1 
Newbie Joined: Sep 2019 From: Canada Posts: 2 Thanks: 0 Math Focus: Algebra  Help turning word problems into equations please...
Hello, my class has just started exploring rational equations. I have no problem solving the equations on their own but when I need to convert information into these equations I can confuse myself. If anyone can help me with turning these two problems into rational equations, I'd be really grateful! 1. A school purchases a load of tshirts with their emblem for \$450. They then put aside two tshirts, and sell the rest for \$560, at \$10 per shirt. How many shirts were in the initial shipment? 2. Two boys are walking for 30km. BoyA walks at a pace 1.4km/h faster then BoyB. BoyA stops during his walk to talk with a friend for 20min, however, he still completes the 30km walk 2hrs before BoyB. How long did they each take to complete the walk? Thank you for your help ! Last edited by SimpleMinded; October 7th, 2019 at 12:26 PM. 
October 7th, 2019, 11:58 AM  #2 
Senior Member Joined: Jun 2019 From: USA Posts: 310 Thanks: 162 
Note: Put a backslash before your dollar signs (\\$). The forum uses dollar signs as a tag for LaTeX code. 1. Let N be the number of tshirts ordered. You are told two things: (a) A school purchases a load of tshirts with their emblem for \$450. Equation: $Buying~cost = \$ 450$ Implied equation: $\$450 = N\cdot (buying~cost~per~shirt)$ (b) Then, they put aside two tshirts and sell the rest for \$560, \$10 per shirt. Equation: $(N2~shirts)\cdot (\$10/shirt) = \$560$ (a) is irrelevant, (b) allows you to find N. 2. "Two boys are walking for 30km." Let $L = 30~km$ be the distance travelled. "BoyA walks at a pace 1.4km/h faster then BoyB." Let $V_A$ and $V_B$ be their respective speeds. Then $V_A = V_B + 1.4~ km/hr$. "BoyA stops during his walk to talk with a friend for 20min" Let $t_A$ and $t_B$ be the time Boy A takes and the time Boy B takes to walk the 30 km. Time is length/speed, so $\displaystyle t_A = \frac{L}{V_A} + \frac{1}{3} hr$. (Note I changed to hours to make the units consistent.) Assume BoyB doesn't stop, $\displaystyle t_B = \frac{L}{V_B}$. "[BoyA] still completes the 30km walk 2hrs before BoyB." $t_A = t_B  2~hr$ I hope this helps. 

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