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 Algebra Pre-Algebra and Basic Algebra Math Forum

 September 17th, 2019, 09:22 AM #11 Global Moderator   Joined: Dec 2006 Posts: 21,035 Thanks: 2271 If x men, each working x hours a day for x days produce x articles in total, where x is a positive constant, it seems reasonable that a*x men, each working b*x hours a day for c*x days, produce abc*x articles (for any non-negative a, b and c). By letting a = b = c = y/x, y men, each working y hours a day for y days, produce (y/x)³x articles, i.e. y³/x² articles. Thanks from Maschke and mathsonlooker October 3rd, 2019, 02:18 PM #12 Newbie   Joined: Jan 2017 From: London Posts: 18 Thanks: 0 I have an update for you guys. I recently went through this with my tutor and here is what she came up with: 1. The total number of hours in the x regime is x^2 i.e. (hours per day)*(days) 2. Therefore, x(total number articles)/x(workers)*x^2 = x/x*x^2 = 1/x^2 (rate of item per worker per hour) 3. Now you simply use this rate for the y regime...so (1/x^2)*y^2*y = y^3/x^2 Tags algebraic, puzzle Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Kavesat Math 1 February 12th, 2017 06:25 AM burgess Algebra 1 June 30th, 2014 12:38 AM Chikis Elementary Math 8 March 2nd, 2014 10:07 AM empiricus Art 11 March 6th, 2011 07:42 AM

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