My Math Forum Proof for a challenging inequality

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 September 14th, 2019, 12:27 PM #1 Newbie   Joined: Sep 2019 From: New York Posts: 3 Thanks: 0 Proof for a challenging inequality I have something I believe to be true, but I'm uncertain, so I'm looking for a proof. For positive real numbers a,b,c,d Prove that if a>=b and c<=d, then a/c <= b/d Last edited by bluekaterpillar; September 14th, 2019 at 12:30 PM.
 September 14th, 2019, 01:12 PM #2 Global Moderator   Joined: May 2007 Posts: 6,835 Thanks: 733 $ad\ge bc$, since $a\ge b$ and $d\ge c$. Divide both sides by $dc$ and get $\frac{a}{c} \ge \frac{b}{d}$. Thanks from topsquark
 September 14th, 2019, 01:17 PM #3 Newbie   Joined: Sep 2019 From: New York Posts: 3 Thanks: 0 Thanks! I can't believe I missed that.

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