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September 5th, 2019, 05:14 AM  #1 
Newbie Joined: Sep 2019 From: PA Posts: 1 Thanks: 0  build an equation?
Good morning. I am having trouble coming up with a way to express an assignment. I am supposed to show how my dad uses math at work expressed in algebretic form. His job is to order medications for a clininic. So, it would look like this: 3 types of medication: med A med B Med C He currently has 38A, 13B, and 4C over the next 2 days he will use medications day F he will use 7A, 4B, and 2C day G he will use 13A, 3B, and 1C so I need to show how many he will need to order if any for the following days Day X he will need 12A, 11B, and 21C Day Y he will need 21A, 8B, and 4C Day Z he will need 6A, 5B, and 3C so the question is, how many of each of 3 medications will he need to order to supply day X,Y, and Z 
September 5th, 2019, 07:58 AM  #2 
Senior Member Joined: Jun 2019 From: USA Posts: 213 Thanks: 90 
You could think of it this way: SA is the anticipated supply of med A at the end of any given day. For example, after days F and G, SA = 38  7  13 TA is the target number of med A he wants to keep in stock at the end of the day. TA = 0 means he will have just enough meds. TA = 20 means he will have 20 extra at the end of the day (common practice to always have extra, because life is not predictable). OA is the number of med A units he will need to order. So, assuming he orders early enough for the meds to be delivered on time, SA + OA = TA (meds previously in stock, minus meds used, plus meds restocked, equals meds remaining) For example, to have just barely enough med A to get through day G, 38713+OA=0 OA = 18 (he still has 18, and doesn't need to order any more). After day Z, 3871312216+OA=0 OA = 21. He would have to have ordered 21 by that point in order not to run out. Do the same for med B and med C, and for whichever days you're looking at. Does that help? 

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